(x/x-3)-(2/x)=(9/x^2-3X)

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Solution for (x/x-3)-(2/x)=(9/x^2-3X) equation: 



(x/x-3)-(2/x)=(9/x^2-3x)

We move all terms to the left:

(x/x-3)-(2/x)-((9/x^2-3x))=0



Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x^2-3x))!=0

x∈R



We add all the numbers together, and all the variables

(x/x-3)-(+2/x)-((9/x^2-3x))=0

We get rid of parentheses

x/x-2/x-((9/x^2-3x))-3=0

Fractions to decimals

-2/x-((9/x^2-3x))-3+1=0

We calculate fractions

We do not support expression: x^3

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